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12.53r^2=14650000
We move all terms to the left:
12.53r^2-(14650000)=0
a = 12.53; b = 0; c = -14650000;
Δ = b2-4ac
Δ = 02-4·12.53·(-14650000)
Δ = 734258000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{734258000}=\sqrt{400*1835645}=\sqrt{400}*\sqrt{1835645}=20\sqrt{1835645}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{1835645}}{2*12.53}=\frac{0-20\sqrt{1835645}}{25.06} =-\frac{20\sqrt{1835645}}{25.06} =-\frac{4\sqrt{1835645}}{5.012} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{1835645}}{2*12.53}=\frac{0+20\sqrt{1835645}}{25.06} =\frac{20\sqrt{1835645}}{25.06} =\frac{4\sqrt{1835645}}{5.012} $
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